National Testing Agency (NTA), CSIR NET December 2025, Eligiblity, Age Limit, Exam Pattern, Apply Online, NTA has released the online applications for Joint CSIR UGC NET December 2025 Examination to determine the eligibility of Indian Nationals for Junior Research Fellowship (JRF) and for Lectureship (LS)/ Assistant Professor in Indian universities and colleges. Candidates who are eligible and interested can apply online by visiting the official website of CSIR NET.
Applications for CSIR NET December 2025 have begun on 25 September 2025, and application forms will be filled until 27 October 2025. The window for making corrections to the application form will be open from 27 to 29 October 2025. The exam will be held on 18 December 2025.
CSIR NET December 2025
National Testing Agency (NTA) : Short Details of Notification
CSIR UGC-NET December 2025 | Short Details of Notification
Important Date
- Application Start : 25 September 2025
- Last Date for Apply Online : 27 October 2025
- Last Date for Fee Payment : 28 October 2025
- Correction Date : 30 October 2025 – 01 November 2025
- Exam Date: 18 December 2025
- City Intimation Slip : Notify Soon
- Admit Card Date : Notify Soon
- Result Date : Notify Soon
Application Fees
- General : 1150/-
- General-EWS/ OBC(NCL) : 600/-
- SC/ ST/ PwBD : 325/-
- Pay the Exam Fee Through Online Mode Credit Card, Debit Card, Net Banking Only.
Age Limit
- Maximum Age : 30 Years (JRF Only)
- Maximum Age : 35 Years (No Limit for Lectureship (LS) / Assistant Professor.)
No. of Post
N/A
Eligibility Criteria
| Exam | CSIR UGC NET Subject | Eligibility |
|---|---|---|
| NTA CSIR UGC NET Examination December 2024 | Chemical Science | General/OBC candidates need at least 55% marks in M.Sc. or an equivalent degree.SC/ST and PH candidates require at least 50% marks.Candidates with an integrated course, B.E/B.Tech, B.Pharma, or MBBS degrees are also eligible. |
| Earth, Atmospheric, Ocean and Planetary Science | ||
| Life Science | ||
| Mathematical Science | ||
| Physical Science |
(Note : For more complete information kindly read the oficial Notification).
Selection Process
- Application Submission
- Admit Card Release
- Examination
- Result Declaration
- Final Selection
Exam Details
| Particulars | CSIR Exam Pattern |
|---|---|
| Exam mode | Online |
| Exam duration | 3 hours |
| Number of subjects | 5 |
| Name of subjects | Earth, Atmospheric, Ocean and Planetary SciencesChemical SciencesLife SciencesMathematical SciencesPhysical Sciences |
| Total questions to attempt | Earth, Atmospheric, Ocean and Planetary Sciences: 75 MCQs Chemical Sciences: 75 MCQs Life Sciences: 75 MCQs Mathematical Sciences: 60 MCQs Physical Sciences: 55 MCQs |
| Type of questions | MCQs; 4 options with only 1 correct option |
| Total marks | 200 |
| Marking scheme | +2 for the correct answer Negative marking of 25 per cent (33 per cent for some parts) |
| Language of paper | English and Hindi |
CSIR NET Exam Pattern 2025 for Chemical Sciences
| Particulars | Part A | Part B | Part C | Total Number |
|---|---|---|---|---|
| Total Questions | 20 | 40 | 60 | 120 |
| Max no of questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 4 | 200 |
| Negative marking of 25% | 0.5 | 0.5 | 1 | – |
CSIR NET Exam Pattern 2025 for Earth Sciences
| Particulars | Part A | Part B | Part C | Total Number |
|---|---|---|---|---|
| Total Questions | 20 | 50 | 80 | 150 |
| Max no of questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 4 | 200 |
| Negative marking- 25% in Part A & B and 33% in Part C | 0.5 | 0.5 | 1.32 | – |
CSIR NET Exam Pattern 2025 for Life Sciences
| Particulars | Part A | Part B | Part C | Total Number |
|---|---|---|---|---|
| Total Questions | 20 | 50 | 75 | 145 |
| Max no of questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 4 | 200 |
| Negative marking of 25% in Part A, B & C | 0.5 | 0.5 | 1 | – |
SIR NET Exam Pattern 2025 for Mathematical Sciences
| Particulars | Part A | Part B | Part C | Total Number |
|---|---|---|---|---|
| Total Questions | 20 | 40 | 60 | 120 |
| Max no of questions to attempt | 15 | 25 | 20 | 60 |
| Marks for each correct answer | 2 | 3 | 4.75 | 200 |
| Negative marking in Part A & B of 25% and no negative marking in Part C | 0.5 | 0.75 | 0 | – |
CSIR NET Exam Pattern 2025 for Physical Sciences
| Particulars | Part A | Part B | Part C | Total Number |
|---|---|---|---|---|
| Total Questions | 20 | 25 | 30 | 75 |
| Max no. of questions to attempt | 15 | 20 | 20 | 55 |
| Marks for each correct answer | 2 | 3.5 | 5 | 200 |
| Negative marking of 25% | 0.5 | 0.875 | 1.25 | – |
CSIR NET December 2025: How to Check & Download
- Visit the official website (https://csirnet.nta.nic.in/) of National Testing Agency (NTA). Candidates Can Apply Between 25 September 2025 to 27 October 2025.
- Candidate Read the Official Notification Before Applying in “CSIR NET December 2025“.
- Kindly Check and Collect the All Document – Eligibility, ID Proof, Address Details, Basic Details.
- Kindly Ready Scan Document Related to Recruitment Form – Photo, Sign, ID Proof, etc.
- Before Submit the Application Form Must Check the Preview and All details Carefully.
- Take A Print Out of Final Submitted Form.
Some Useful Important Links
| Apply Online | Click Here |
| Download Notification | Click Here |
| Download Information Bulletin | Click Here |
| Official Website | https://csirnet.nta.nic.in/ |
| Age Calculator tool | Click Here |
| More Recruitments | Click Here |

CSIR NET December 2025- Important Question
When will the online application for NTA CSIR NET December 2025 Start?
The online application for this examination has started on 25 September 2025.
What is the last date for online application for this examination?
The last date to sumbit the online application Form is 27 October 2025.
What is the official website for NTA CSIR?
The official website for NTA CSIR UGC NET is https://csirnet.nta.nic.in/.
What is the age limit for NTA CSIR NET December 2025?
The age limit for NTA CSIR UGC NET December 2025 is as follows:
What is the eligibility for NTA CSIR NET December 2025?
General/OBC candidates must have a minimum of 55% marks in MSc or equivalent degree. See the official notification for more details.
